![]() ![]() It works by taking the input value in newton meters and applying the conversion factor of 0.73756214728 foot pounds per newton meter. © Copyright 2000 - 2023, by Engineers Edge, LLC All rights reserved.The newton meters (Nm) to foot pounds (ft-lb) converter is a simple and efficient tool used to convert torque from newton meters to foot pounds. ![]() Modified by Administrator at Thu, Feb 14, 2008, 11:47:48 In your exemple : the equation of a force (newtons) is M*L*T^-2, but the equation of a couple is (M*L*T^-2)*L = M*L^2*T^-2.Ī good reference site (but alas n french is : -Removed Commercial Link. It can help you to verify the consistency of some complex equations. If you use that method, you know immediately if quantities you are comparing are of same nature. The "dimensionnal equation" of a speed, for instance, is L*T^-1. Non measurable entities can be introduced, but this is another problem. There is a simple mean of not worrying with systems of units, it is to use what we call in French "equations aux dimensions" (I don't know the translation in english).Īny measurable quantity can be expressed in terms of mass, length, intensity, time. : : : : : : How do you covert Weight to Newton meter - fkhouckįirst, I apologize for my poor english. : : : : : : How do you covert Weight to Newton meter Watts is then converted into the American standard for power called horsepower by dividing watts by 745.7.Ģ13,015.69 watts/ 745.7 watts = 285.66 horsepowerīeer, Ferdinand P., Johnston, E. Then the power is found by multiplying the angular velocity times torque In order to convert foot pounds of torque to Newton meters of force one uses this equation. Implementing the engine's frequency into the equation of angular velocity w = 2 * p * f ![]() The frequency of the engine is calculated by:į = (5000 revolutions per minute) / (60 seconds) There is 3.28 feet in a meter, and 4.448 Newtons in a pound, which will be needed since the experimental engine's torque is rated in foot pounds force. All I am trying to do is determine what wattage is possible from a given weight. And that is what I used for the foot pounds. If I had 10 pounds that would return 10 foot pounds. To get torque you multiply weight * the distance from the center. The only problem that I see is the way I achieved foot pounds. I found this formula on the web and I have worked it out on a spread sheet. Thanks for all the help, I really needed it. : : : : : How do you covert Weight to Newton meter - jboggs : : : : : How do you covert Weight to Newton meter Just tell us the details and someone here can check your formulas and math. I think the easiest thing would be for you to just tell us what exactly are you trying to do and how you will you use it. But you cannot convert, for example, Mass to Force, or Torque to Work, without some other factor. Conversion between imperial and metric units of measure is a very straightforward process - simply apply a conversion factor. And they each have both imperial and metric units of measure. Mass, Weight, Force, Torque, Energy, Work, and Power are all related but they are different things. Not only are you mixing units, you are mixing systems. : : : : How do you covert Weight to Newton meter - fkhouckĬareful there. : : : : How do you covert Weight to Newton meter I specialize in main frame computers and I know how troublesome weekend warriors can be. If I were to multiply gravity times the pounds I would return (Newtons) or pound-force.Īnd I apologize if this is to elemental for you, and I mean that. Gravity is a know entity and from it we can gather information on both its potential force its weight and the speed at which it will accelerate. Weight itself is a measure of potential force, with out gravity it would be reduced to mass only. My view although well understood is not as sophisticated as yours, and certainly only based on a common knowledge view is. I just am not certain on how I could do it. I knew I had to make the conversion from weight to force. You can convert pounds to force (Newtons) by multiplying by gravity (for things that stay still) or acceleration more generally." The quote that I find most encouraging is this: I am clearly aware that there is a distinction between the two. And is exactly the state of confusion that I am in. Both very good comments and to the point. ![]()
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